Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    // Write your pointer logic here
    if (k < 1) {
        return 0;
    } else if (k < 2) {
        return 1;
    }

    int pat1 = *mem;
    mem++;
    int pat2 = *mem;

    if (pat2 == pat1){
        return 0;
    }
    mem++;

    int i = 2;
    while (i < k) {
        if (i % 2 == 0) {
            if (*mem != pat1) {
                return 0;
            }
        } else {
            if (*mem != pat2) {
                return 0;
            }
        }
        i++;
        mem++;
    }

    return 1;
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach