Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    // Write your pointer logic here
// 1 0 1 0
if(k<=2) {
    return 1;
}
    for(int i=2;i<k;i++) {
        int target=(i%2)?(*(mem+1)):(*mem);
        if(*(mem+i)!=target)
            return 0;
    }
    return 1;
}
// 1 0 1 0 1 0
int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach