Detect Alternating Pattern

Code

#include <stdio.h>

int is_alternating_pattern(int *mem, int k) {
    // Write your pointer logic here
    int *start = mem;
    int *end = mem + k -2;
    int i = 0;
    while(start < end)
    {
        printf("*mem: %d *(mem+2): %d\n", *start, *(start+2) );
        // if( (mem[i] == mem[i+2]) && (mem[i] != mem[i+1]) )
        if( (*start == *(start+2)) && (*start != *(start+1)) )
        {
            // return 1;
        }
        else{
            return 0;
        }
        ++start;
    }
    return 1;
}

int main() {
    int n, k, arr[100];
    scanf("%d %d", &n, &k);

    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int res = is_alternating_pattern(arr, k);
    printf("%d", res);

    return 0;
}

Solving Approach