Double Pointer

Code

#include <stdio.h>

void reassign_based_on_value(int **pp, int *n2_ptr) 
{
    if((**pp)%2) //as it is double pointer, we need to derefernce it twice, then only we can find if it is even or odd number.
      return ;
    
    **pp=*n2_ptr;

}

int main() 
{
    int n1, n2;
    scanf("%d %d", &n1, &n2);

    int *p = &n1; 

    reassign_based_on_value(&p, &n2);

    printf("%d", *p);

    return 0;
}

Solving Approach