Double Pointer

Code

#include <stdio.h>

void reassign_based_on_value(int **pp, int *n2_ptr) {
    // Your logic here
    int n1_val = **pp;   // value of n1 (since p initially points to n1)
    if (n1_val % 2 == 0) 
    {  
        *pp = n2_ptr;   // reassign if n1 is even
    }
}

int main() {
    int n1, n2;
    scanf("%d %d", &n1, &n2);

    int *p = &n1;

    reassign_based_on_value(&p, &n2);

    printf("%d", *p);

    return 0;
}

Solving Approach