Double Pointer

Code

#include <stdio.h>
#include <stdlib.h>

int main() {
    int n1, n2;
    scanf("%d %d", &n1, &n2);

    int *p = &n1;
    int **pp = &p;
	if(*p % 2 == 0){
		p = &n2;
	}
	else p = &n1;
	printf("%d", *p);

    return 0;
}

Solving Approach