Extract and Modify Field in a 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t update_register(uint32_t reg) {
    // Your logic here
    uint8_t field = ((reg >> 10) & 0x1f);
    field = 31 > field? field + 1 : field;

    reg &= ~(0x1f << 10); // clear field
    reg |= (field << 10); // set field

    return reg;
}

int main() {
    uint32_t reg;
    scanf("%u", &reg);
    uint32_t updated = update_register(reg);
    printf("%u", updated);
    return 0;
}

Solving Approach

My logic is similar to the solution

 

 

 

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Input

15360

Expected Output

16384