Extract Bit Field from 16-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t extract_field(uint16_t reg) {
    uint16_t mask = 0x1F;
    uint8_t field = (reg >> 4) & mask;
    return field;
}

int main() {
    uint16_t reg;
    scanf("%hx", &reg);
    printf("%u", extract_field(reg));
    return 0;
}

Solving Approach

• reg >> 4 shifts bits 4–8 to positions 0–4.
• & mask ensures only 5 bits are kept.
• Return the value so main prints it