Extract Even Bits Only from 32-bit Register

#include <stdio.h>
#include <stdint.h>

uint32_t extract_even_bits(uint32_t reg) {
    uint8_t i;
    uint16_t var = 0x0000; //result variable initially all bits are set to zero
    for(i=0;i<16;i++){     
        if((reg>>(2*i)) & 1){   //check if the even position is 1
            var = var | (1<<i);  // set the corresponding bit here
        }
    }
    return var; 
  }

int main() {
    uint32_t reg;
    scanf("%u", &reg);
    printf("%u", extract_even_bits(reg));
    return 0;
}

Solving Approach

 

 

 

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Input

85

Expected Output

15