Extract Even Bits Only from 32-bit Register

#include <stdio.h>
#include <stdint.h>

uint32_t extract_even_bits(uint32_t reg) {
    // Your code here
    uint16_t reg_1=0;
    uint8_t val=0;
    for (unsigned int i=0;i<32;i+=2){
         val = ((reg >> i) & 0x01);
         reg_1|= (val<<(i/2));
    }
   return reg_1;
}

int main() {
    uint32_t reg;
    scanf("%u", &reg);
    printf("%u", extract_even_bits(reg));
    return 0;
}

Solving Approach

 

 

 

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Input

85

Expected Output

15