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Extract Even Bits Only from 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t extract_even_bits(uint32_t reg) {
    // Your code here
    int n = 0;
    uint32_t evenReg = 0b0;
    for(size_t i = 0; i<32; i+=2){
     //shift the even positions of reg to position 0 and extract.
     //Next thing is to put the extracted bit in the required position in evenReg   
    evenReg |= ((reg>>i) & 1)<<n;
    n++;
    }
    return evenReg;
}

int main() {
    uint32_t reg;
    scanf("%u", &reg);
    printf("%u", extract_even_bits(reg));
    return 0;
}

Solving Approach

shift the even positions of the  register to position 0 and extract.

  Next thing is to put the extracted bit in the required position in even register.

 

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Input

85

Expected Output

15