Extract Even Bits Only from 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t extract_even_bits(uint32_t reg) {
    // Your code here
    uint32_t result=0; 
    for(uint8_t pos=0; pos<31; pos+=2){
        uint8_t current_bit = (reg >> pos) & 1; 
        result |= (current_bit << (pos/2));
    }
    return result; 
}

int main() {
    uint32_t reg;
    scanf("%u", &reg);
    printf("%u", extract_even_bits(reg));
    return 0;
}

Solving Approach