Extract Even Bits Only from 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t extract_even_bits(uint32_t reg) {
    // Your code here
    uint32_t ret = 0;

    for (uint8_t i = 0; i < 32; i += 2) {
            // my logic
            // ret <<= 1;
            // ret |= ((reg >> (30-i)) & 0x1);

            // With solution
            ret |= (((reg >> i) & 1) << (i / 2));
    }

    return ret;
}

int main() {
    uint32_t reg;
    scanf("%u", &reg);
    printf("%u", extract_even_bits(reg));
    return 0;
}

Solving Approach

Loop & shift

I've modified my logic with the solution