Extract Even Bits Only from 32-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint32_t extract_even_bits(uint32_t reg) {
    // Your code here
    uint32_t ans;
    for(int i=0; i<16; i++){
        ans |= ((reg >> 2*i) &1) << i;
    }
    return ans;
}

int main() {
    uint32_t reg;
    scanf("%u", &reg);
    printf("%u", extract_even_bits(reg));
    return 0;
}

Solving Approach

check even bits by >> by 2*i times and & 1 to get the whether even is set or clear. Then insert that bit into answer at position i by oring left shifted by i.