Find Maximum Element Using Pointer Walk

Code

#include <stdio.h>

int find_max_element(int *ptr, int n) {
    // Your logic here
    int temp;
    for(int i = 0;i <n;i++){
        for(int j = i+1;j<n;j++){
            if(*(ptr + i) > *(ptr + j)){
                temp = *(ptr + i);
                *(ptr + i) = *(ptr + j);
                *(ptr + j) = temp;
            }
        }
    }
    return *(ptr + (n - 1));
}
int  test(int arr[], int n){ //trong khai báo arr[] = *arr
    int arr2[5]; // Mảng phải có số lượng size
    int temp;
    for(int i = 0; i < n; i++){ //De 2 mang bang nhau
        arr2[i] = arr[i];
    }
    for(int i = 0;i<n;i++){
        for(int j =0;j<n;j++){
            if(arr[i] < arr[j]){
                temp = arr[i];
                arr[i] = arr[j];
                arr[j] = temp;
            }
        }
    }
    return arr[n-1];
}

int main() {
    int n;
    scanf("%d", &n);

    int arr[100];
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    int result = find_max_element(arr, n);
    // int result = test(arr, n);
    printf("%d", result);

    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

5 10 25 5 30 15

Expected Output

30