108. Find Minimum and Maximum in an Array

Back To All Submissions
Previous Submission
Next Submission

Code

#include <stdio.h>
#include <stdint.h>

void find_min_max(uint8_t *arr, uint8_t n, uint8_t *min, uint8_t *max) {
    // Your logic here
    int i =0;
    if(n%2 ==1){
        *min = *max = arr[0];
        i++;
    }
    else{
        if(arr[0]>arr[1]){
            *min = arr[1]; *max = arr[0];
        }
        else{
            *min = arr[0]; *max = arr[1];
        }
        i+=2;
    }
    int temp_min = *min;
    int temp_max = *max;
    while(i<n){
        if(arr[i]<arr[i+1]){
            temp_min = arr[i];
            temp_max = arr[i+1];
        }
        else{
            temp_min = arr[i+1];
            temp_max = arr[i];
        }
        i+=2;
        if(temp_min < *min)
            *min = temp_min;
        if(temp_max > *max)
            *max = temp_max;
    }
}

int main() {
    uint8_t n;
    scanf("%hhu", &n);
    uint8_t arr[100];

    for (uint8_t i = 0; i < n; i++) {
        scanf("%hhu", &arr[i]);
    }

    uint8_t min_val, max_val;
    find_min_max(arr, n, &min_val, &max_val);

    printf("%hhu %hhu", min_val, max_val);
    return 0;
}

Solving Approach

 

 

 

Was this helpful?
Upvote
Downvote