#include <stdio.h>
int add(int a, int b) { return a + b; }
int sub(int a, int b) { return a - b; }
int mul(int a, int b) { return a * b; }
int divide(int a, int b) { return a / b; }
int execute_command(int a, int b, int cmd) {
// Your logic here using function pointer array
// create an array of pointers_to_function
int(*arr[4])(int,int)={add,sub,mul,divide};
int result;
result=arr[cmd](a,b);
return result;
}
int main() {
int a, b, cmd;
scanf("%d %d %d", &a, &b, &cmd);
int result = execute_command(a, b, cmd);
printf("%d", result);
return 0;
}Solving Approach
now for declaring array of pointers , which point to functions having return type and arguments.
The syntax is important : return_type_of_function (*array_name[size_of_array])(argument_data_types)={function name....};
Ex: int (*arr[4])(char,int) ={fun1,fun2,fun3,fun4};
return type of 4 functions is int and each function has arguments of type-char, int ;
Input
10 5 0
Expected Output
15