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Function Pointer Dispatch Table

Code

#include <stdio.h>

int add(int a, int b) { return a + b; }
int sub(int a, int b) { return a - b; }
int mul(int a, int b) { return a * b; }
int divide(int a, int b) { return a / b; }

int execute_command(int a, int b, int cmd) {
    // Your logic here using function pointer array
    int (*ptr)(int,int)=add;
      int (*ptr1)(int,int)=sub;
        int (*ptr2)(int,int)=mul;
          int (*ptr3)(int,int)=divide;
          if(cmd==0)
          {
            int r=0;
            r=ptr(a,b);
            return r;
          }
        else  if(cmd==1)
          {
            int r=0;
            r=ptr1(a,b);
            return r;
          }
         else if(cmd==2)
          {
            int r=0;
            r=ptr2(a,b);
            return r;
          }
         else if(cmd==3)
          {
            int r=0;
            r=ptr3(a,b);
            return r;
          }
          
    
}

int main() {
    int a, b, cmd;
    scanf("%d %d %d", &a, &b, &cmd);

    int result = execute_command(a, b, cmd);
    printf("%d", result);

    return 0;
}

Solving Approach

int (*ptr)(int,int)=add;
      int (*ptr1)(int,int)=sub;
        int (*ptr2)(int,int)=mul;
          int (*ptr3)(int,int)=divide;
          if(cmd==0)
          {
            int r=0;
            r=ptr(a,b);
            return r;
          }
        else  if(cmd==1)
          {
            int r=0;
            r=ptr1(a,b);
            return r;
          }
         else if(cmd==2)
          {
            int r=0;
            r=ptr2(a,b);
            return r;
          }
         else if(cmd==3)
          {
            int r=0;
            r=ptr3(a,b);
            return r;
          }
          
    

 

 

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Input

10 5 0

Expected Output

15