Is the Bit Set

Code

#include <stdio.h>
#include <stdint.h>

uint8_t is_bit_set(uint8_t reg, uint8_t pos) {
    // Your code here

    return ( (reg >> pos) & 1 );
}

int main() {
    uint8_t reg, pos;
    scanf("%hhu %hhu", &reg, &pos);
    printf("%u", is_bit_set(reg, pos));
    return 0;
}

Solving Approach

-> shift the specific bit, that is to be checked to the LSB.
-> AND it with 1 and return the value of the operation ; if its 1 the bit is set else otherwise.