Keep Only the Highest Set Bit

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
uint16_t highest_set_bit(uint16_t reg) {
    // Your logic here
    uint8_t hsb_placement = 0;
    for(int i = 0; i < 16; i++){
        if ((reg & (1<<i)) >> i) hsb_placement = i;
    }

    return hsb_placement ? (1<<hsb_placement) : 0;
}

int main() {
    uint16_t reg;
    scanf("%hu", &reg);

    uint16_t result = highest_set_bit(reg);
    printf("%hu", result);
    return 0;
}

Solving Approach

First pass code. Very crude solving but the jist is, the program checks each bit if they're a before recording the highest 1 bit position. If the highest placement is 0, we return 0 but if the highest placement is greater than zero, then we bit shift one by the high placement and return it.