Left Rotate Array by K Positions

Code

#include <stdio.h>
void reverse_array(int arr[], int start, int end){
    while(start<end){
          int tempt=arr[start];
          arr[start]=arr[end];
          arr[end]=tempt; 
          start++;
          end--;
    }
}

void rotate_left(int arr[], int n, int k) {
    // Your logic here
    k=k%n;
    reverse_array(arr,0, k-1);
    reverse_array(arr, k, n-1);
    reverse_array(arr,0,n-1 );
    
}

int main() {
    int n, k;
    scanf("%d %d", &n, &k);

    int arr[100];

    // Read array elements
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    // Rotate the array
    rotate_left(arr, n, k);

    // Print the rotated array
    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
        	printf(" ");
        }
    }

    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

5 2 1 2 3 4 5

Expected Output

3 4 5 1 2