Left Rotate Array by K Positions

Code

//  Left Rotate Array by K Positions
#include <stdio.h>

void left_rotate(int *arr, int k, int n){
    int tmp = 0; 
    for(int i = 0; i < k; i++){
        tmp  = arr[0];
        for(int j = 0; j < n - 1; j++){
            arr[j] = arr[j+1]; 
        }
        arr[n-1] = tmp;  
    }
}

int main(){
    int n, k, arr[100]; 
    scanf("%d %d",&n ,&k); 
    for(int i = 0; i < n; i++){
        scanf("%d",&arr[i]);
    }

    left_rotate(arr,k,n);
    for(int i = 0; i<n; i++){
        printf("%d", arr[i]);
        if(i < (n-1)){
            printf(" "); 
        }
    }
    return 0;
} 

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

5 2 1 2 3 4 5

Expected Output

3 4 5 1 2