Left Rotate Array by K Positions

Code

#include <stdio.h>

void rotate_left(int arr[], int n, int k) {
    // Your logic here
    int left_arr = 0;
    int right_arr = n-1;
    if(k >= n){
        k = k%n;
    }
    for(int i = 0; i<k; i++){
        int temp = arr[left_arr];

        for(int j = 0; j<= n-k; j++){
            arr[j] = arr[j+1];
        }
        arr[right_arr] = temp;
    }
    
    
}

int main() {
    int n, k;
    scanf("%d %d", &n, &k);

    int arr[100];

    // Read array elements
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    // Rotate the array
    rotate_left(arr, n, k);

    // Print the rotated array
    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
        	printf(" ");
        }
    }

    return 0;
}

Solving Approach