Left Rotate Array by K Positions

Code

#include <stdio.h>

void reversal(int a[], int left, int right) {
    
    while (left < right) {
        int temp = a[left];
        a[left] = a[right];
        a[right] = temp;

        left++;
        right--;
    }        
}

void rotate_left(int arr[], int n, int k) {
    // Your logic here
    k = k % n;  // Normalize k if it's greater than n

    reversal(arr, 0, k-1);
    reversal(arr, k, n-1);
    reversal(arr, 0, n-1);

}

int main() {
    int n, k;
    scanf("%d %d", &n, &k);

    int arr[100];

    // Read array elements
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    // Rotate the array
    rotate_left(arr, n, k);

    // Print the rotated array
    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
        	printf(" ");
        }
    }

    return 0;
}

Solving Approach

 

 

 

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Input

5 2 1 2 3 4 5

Expected Output

3 4 5 1 2