Left Rotate Array by K Positions

Code

#include <stdio.h>



void reverse_array(int* arr, int i, int j)
{
    int temp = 0;
    while(i < j)
    {
        temp = arr[i];
        arr[i] = arr[j];
        arr[j] = temp;
        i++;
        j--;
    }
}

void rotate_left(int arr[], int n, int k) {
    // Your logic here
    k = k%n;
    //reverse first k elements
    reverse_array(arr, 0, k-1);

    //reverse next n-k elements
    reverse_array(arr, k, n-1);

    //reverse whole array
    reverse_array(arr, 0, n-1);
}

int main() {
    int n, k;
    scanf("%d %d", &n, &k);

    int arr[100];

    // Read array elements
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    // Rotate the array
    rotate_left(arr, n, k);

    // Print the rotated array
    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
        	printf(" ");
        }
    }

    return 0;
}

Solving Approach