Left Rotate Array by K Positions

Code

#include <stdio.h>
#include <stdint.h>

void rotate_left(int arr[], int n, int k) {
    // Your logic here
   int cnt=0;
   int tmp=0;
   int tmp1=0;
   while (cnt<k){
       tmp=arr[n-1];

       arr[n-1]=arr[0];



       for (int i=n-2;i>=0;i--){
             tmp1=arr[i];
             arr[i]=tmp;
             tmp=tmp1;
       }


       cnt++;

   }
    
}

int main() {
    int n, k;
    scanf("%d %d", &n, &k);

    int arr[100];

    // Read array elements
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    // Rotate the array
    rotate_left(arr, n, k);

    // Print the rotated array
    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
        	printf(" ");
        }
    }

    return 0;
}

Solving Approach