Left Rotate Array by K Positions

Reversing array

#include <stdio.h>

void rev(int arr[], int start, int end){
    while(start < end){
        int temp = arr[start];
        arr[start++] = arr[end];
        arr[end--] = temp;
    }
}

void rotate_left(int arr[], int n, int k) {
    // Your logic here
    k %= n;
    rev(arr, 0, k-1);
    
    rev(arr, k, n-1);

    rev(arr, 0, n-1);
}

int main() {
    int n, k;
    scanf("%d %d", &n, &k);

    int arr[100];

    // Read array elements
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    // Rotate the array
    rotate_left(arr, n, k);

    // Print the rotated array
    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
        	printf(" ");
        }
    }

    return 0;
}

Solving Approach

reversing the arrays in split parts , then reverse full array to mimic left rotation.