Left Rotate Array by K Positions

Code

#include <stdio.h>

void rotate_left(int arr[], int n, int k) {
    // Your logic here
    int temp;
    k = k%n;
    int r;
    if(k==0) return;
    for(int l=0,r=k-1;l<r;l++,r--){
        temp = arr[l];
        arr[l] = arr[r];
        arr[r] = temp;
    }
    for (int l = k, r = n - 1; l < r; l++, r--) {
        temp = arr[l];
        arr[l] = arr[r];
        arr[r] = temp;
    }
    for (int l = 0, r = n - 1; l < r; l++, r--) {
        temp = arr[l];
        arr[l] = arr[r];
        arr[r] = temp;
    }
}

int main() {
    int n, k;
    scanf("%d %d", &n, &k);

    int arr[100];

    // Read array elements
    for (int i = 0; i < n; i++) {
        scanf("%d", &arr[i]);
    }

    // Rotate the array
    rotate_left(arr, n, k);

    // Print the rotated array
    for (int i = 0; i < n; i++) {
        printf("%d", arr[i]);
        if(i < n-1){
        	printf(" ");
        }
    }

    return 0;
}

Solving Approach