Modify Bytes in a 32-bit Value Using Union

Code

#include <stdio.h>
#include <stdint.h>

typedef union {
    uint32_t value;
    uint8_t bytes[4];
} Register;

// Write logic here using union to modify byte[1] and byte[2]
void modify_and_print(uint32_t input, uint8_t b1, uint8_t b2) {
    // Your logic here
    Register un;
    un.value = input;
    // printf("%d ",input);
    // printf("%d ",un.value);
    un.bytes[1]=b1;
    un.bytes[2]=b2;
    printf("%u ",un.value);
    // printf("%d ",un.bytes[0]);
    // printf("%d ",un.bytes[1]);
    // printf("%d ",un.bytes[2]);
    // printf("%d ",un.bytes[3]);
}

int main() {
    uint32_t num;
    uint8_t b1, b2;
    scanf("%u %hhu %hhu", &num, &b1, &b2);
    modify_and_print(num, b1, b2);
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

305419896 170 187

Expected Output

314288760