Parse Comma-Separated Integers into an Array

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    uint8_t digits[3];
    uint8_t num_of_digits = 0;
    uint8_t write_index = 0;

    // while(*str!='\0'){
    uint8_t str_len=0;
    while(str_len<101){
        if((*str==',')||(*str=='\0')){
            //store collected number
            uint8_t val =0;
            uint8_t mult = 1;
            for(uint8_t i=0; i<num_of_digits; i++){
                val+= digits[num_of_digits-i-1]*mult;
                mult = mult*10; 
            }
            arr[write_index] = val;
            write_index++;
            num_of_digits=0;

            if((*str=='\0')){break;}
        }
        else{
            digits[num_of_digits] = (*str)-'0';
            num_of_digits++;
        }
        str++;
        str_len++;
    }
    *count = write_index;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}