97. Parse Comma-Separated Integers into an Array

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Code

#include <stdio.h>
#include <stdint.h>
#include <stdlib.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    uint8_t result[100];
    int resPos = 0;
    int i = 0;

    char temp[10];
    int j = 0;
    
    while(str[i] != '\0')
    {
        if (str[i] == ',')
        {
            *(temp + j) = '\0';
            *(result + resPos) = atoi(temp);
            resPos++;
            j = 0;
        } else {
            *(temp + j) = str[i];
            j++;
        }
        i++;
    }
    *(temp + j) = '\0';
    *(result + resPos) = atoi(temp);

    i = 0;
    while(i <= resPos) 
    {
        printf("%u ", *(result + i));
        i++;
    }

}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach

 

 

 

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