Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    char *num;
    uint8_t n = 0;
    while(*str != '\0')
    {
        if(*str == ',')
        {   
            *arr = n;
            *count += 1;
            // numlen = 0;
            n=0;    
            arr++;
        }
        else
        {
            // *num = *str;
            n = n*10 + (*str - '0');
            // numlen++;
            // num++;
        }
            str++;
    }
    *count+=1;
    *arr = n;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

10,20,30

Expected Output

10 20 30