Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    uint8_t local_arr[3];
    uint8_t i = 0, j = 0, sum = 0, hun = 1, condition = 0;
    while(!condition)
    {
        if(str[j]=='\0')
            condition = 1;
        if(str[j]==',' || str[j]=='\0')
        {
            while(i>0)
            {
                i--;
                sum += ((local_arr[i] - '0') * hun);
                hun *= 10;
            }
            arr[(*count)++] = sum;
            hun = 1;
            sum = 0;
        }
        else
            local_arr[i++] = str[j];
        j++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach