Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    int len;
    for(len=0;str[len]!='\0';len++);

    //number of commas
    int i;
    uint8_t k=1;
    for(i=0;i<len;i++){
        if(str[i] == ',') k++;
    }



    *count = k;

    int j,l=0;
    int sum=0;
    for(j=0;j<k;j++){
        sum=0;
        while(str[l] != ',' && str[l]!='\0'){
            //printf("\n %c",str[l]);
            char temp=0;
            temp = str[l] - '0';
            sum = sum * 10;
            sum += temp;
            l++;
            
        }
        l++;
        arr[j] = sum;
    }
    

}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach