Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>
#include <math.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    int i=0,j=0,k=0;
    int num=0;
    while(1)
    {
        if(str[j]!=',' && str[j]!='\0' )
        {
            k++;
           
        }
        else if(str[j]==','||str[j]=='\0')
        {
            for(i=j-k;i<j;i++)
            {
               
                num=num+(str[i]-48)*pow(10,(--k));
                 //printf("num1: %d\n",num);

            }
            *count+=1;
            *arr++=num;
            num=0;

        }
        if(str[j]=='\0')
        {
            break;
        } 

        j++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach