Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>

int power(int num, int exp)
{
    int result = 1;
    while(exp--)
    {
        result *= num;
    }
    return result;
}
void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here

    int len = -1;
    while(str[++len] != '\0');

    int idx = 0;
    int num = 0;
    int exp = 0;

    int temp[255] = {0};
    int x =0;
    for(int i=0; i<len; ++i)
    {
        exp =0;
        x= 0;
        num = 0;
        while((str[i] != ',') && (str[i] != '\0'))
        {
            temp[x++] = str[i] - '0';
            i++;
        }

        for(int i=(x-1); i>=0; --i)
        {
            num += temp[i]*power(10,exp);
            exp++;
        }
            arr[idx++] = num;
    }
    *count = idx;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach