Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>

uint8_t convertToNumber(const char *str,uint8_t ucDigits)
{
    uint8_t number = 0,idx;
    for(idx= 0;idx < ucDigits;idx++)
    {
        number = (number*10) + str[idx] - '0';
    }
    return number;
}
void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    const char *ptr;
    *count = 0;
    while(*str != '\0')
    {
        ptr = str;
        while((*str != ',') && (*str != '\0'))
        {
            str++;
        }
        arr[(*count)++] = convertToNumber(ptr,str-ptr);
        if((*str != '\0'))
        {
            str++;
        }
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach