Parse Comma-Separated Integers into an Array

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here ghi lai
    char chuoi[10];
    int k =0, j =0;
    for(int i =0; str[i] != '\0'; i++){
        if(*(str + i) >= '0' && *(str + i) <= '9'){
            k = 0;
            while(str[i] != ',' && str[i] != '\0'){
                chuoi[k] = *(str + i);
                k++;
                i++;
            }
            chuoi[k] = '\0';
            int so = 0;
            for (int t = 0; chuoi[t] != '\0'; t++) {
                so = so * 10 + (chuoi[t] - '0');
            }
            arr[*count] = so;
            (*count)++;
        }

    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}