Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    int cc=0,i=0,num=0;
    while(true){
        if(*str=='\0'){
            arr[cc]=num;
            cc++;
            printf("%d ",num);
            break;
        }
        if(*str==','){
            arr[cc]=num;
            cc++;
            printf("%d ",num);
            num=0;
            i=0;
        }
        else{
            int a=((int)*str)-48;
            num=num*10+a;
            i++;
        }
        str++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach