Parse Comma-Separated Integers into an Array

#include <stdio.h>
#include <stdint.h>

uint8_t get_number(char* number_str, uint8_t n){
    uint8_t number = 0;
    for (size_t i=0; i<n; i++){
        uint8_t num = ((uint8_t)*(number_str+i)) - '0';
        switch (n-i){
            case 3:
                num *= 100;
                break;
            case 2:
                num *= 10;
                break;
        }
        number += num;
    }
    return number;
}

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    char number_str[3];
    uint8_t number_n = 0;
    for (size_t i=0; i<255; i++){
        char chr = *(str+i);
        if (chr != ',' & chr != '\0'){
            number_str[number_n] = chr;
            number_n++;
        } else {
            uint8_t number = get_number(number_str, number_n);
            *(arr + *count) = number;
            (*count)++;
            number_n = 0;
            if (chr == '\0'){
                return;
            }
        }
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}