97. Parse Comma-Separated Integers into an Array

Back To All Submissions
Previous Submission
Next Submission

Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    int current_num = 0;
    int has_digit = 0;

    for (int i = 0; str[i] != '\0'; i++) {
        if (str[i] >= '0' && str[i] <= '9') {
            current_num = (current_num * 10) + (str[i] - '0');
            has_digit = 1;
        }
        else if (str[i] == ',') {
            if (has_digit) {
                arr[*count] = (uint8_t)current_num; 
                (*count)++;                         
                current_num = 0;                    
                has_digit = 0;
            }
        }
    }

    // 3. Save the very last number (since strings don't end with a comma)
    if (has_digit) {
        arr[*count] = (uint8_t)current_num;
        (*count)++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach

 

 

 

Was this helpful?
Upvote
Downvote