97. Parse Comma-Separated Integers into an Array

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Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    int i=0, temp=0, index=0;;
    while(1) {
        if(*(str + i) == '\0') {
            *(arr + index) = temp;
            *count+=1;
            index++;
            temp=0;
            break;

        }
        if(*(str + i) == ',') {
            *(arr + index) = temp;
            *count+=1;
            index++;
            temp=0;

        }
        else {
            temp = temp*10 + (*(str + i) - '0');

        }
        i++;
        
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach

 

 

 

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