Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    int i = 0;
    int mun = 0;
    int index = 0;
    if(str[0] == '\0'){
        *count = 0;
        return ;
    }
    while(str[i] != '\0'){
        if(str[i] >= '0' && str[i]<= '9'){
            mun = (mun * 10) + str[i] - '0';
        }
        else if(str[i] == ','){
            arr[index] = (uint8_t)mun;
            index++;
            mun = 0;
        }
        i++;
    }
    arr[index] = (uint8_t)mun;
    index++;
    *count = index;
}
        


int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach