Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>
#include <string.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    int i,j,x,sum,k,y;
    sum=0;k=0,j=0;;
    x=strlen(str);
    for(i=0;i<x;i++){
        if(str[i]>='0'&&str[i]<='9'){
            sum=sum*10+(str[i]-48);}
        else{
        arr[k++]=sum;
        sum=0;}
    }
    arr[k]=sum;
    *count=k+1;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach

 

 

 

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Input

10,20,30

Expected Output

10 20 30