97. Parse Comma-Separated Integers into an Array

Back To All Submissions
Previous Submission
Next Submission

Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    int len = 0;
    int flag = 0;
    uint8_t current_number = 0;
    uint8_t temp[10];
    while (*(str + len) != '\0') {
        len ++;
    }
    for (int i = 0; i <= len ; i ++) {
        char ch = *(str + i);
        if (ch >= '0' && ch <= '9') {
            current_number = (current_number*10) + (ch - '0');
            flag = 1;
        }
        else if (ch == ',' || ch == '\0') {
            if (flag == 1) {
                *(arr + (*count)) = current_number;
                *(count) += 1;
                current_number = 0;
                flag = 0;
            }
        }
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach

 

 

 

Was this helpful?
Upvote
Downvote