Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    /*
    given: csv str, val in 0-255; return: arr[uint8_t]
    loop until null char
    check for commas
    validate val is in range 0-255
    append to array, count++
    validate arr size == count
    --------------------------
    0-9 (48-57)
    */
    uint8_t num = 0;
    while (*str != '\0'){
        
        if (*str >= '0' && *str <= '9'){
            uint8_t temp_digit = *str - '0';
            num = (num * 10) + temp_digit;
        }
          
        else if (*str == ','){
            arr[(*count)++] = num;
            num = 0;
        }
        str++;
    }
    
    arr[(*count)++] = num;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach