Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>
#include<stdlib.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
int index = 0;
char new_str[10] ;
    *count = 0;
    while(*str)
    {   
        if(*str>='0' &&*str<='9')
        {   new_str[index++] = *str;
            
        }
       else if(*str == ',' || *str =='\0')
       {
        if(index>0)
        {
            new_str[index]='\0';
            arr[*count]= (uint8_t)atoi(new_str);
            (*count)++;
            index = 0;
        }
       }
       str++;
    } 

     if(index>0)
        {
            new_str[index]='\0';
            arr[*count]= (uint8_t)atoi(new_str);
            (*count)++;
            index = 0;
        }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach