#include <stdio.h>
#include <stdint.h>
void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count);
// void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
// int value = 0,j=0;
// for(int i=0; str[i]!='\n'; i++){
// int c = str[i];
// if( c>='0' && c<='9'){
// value = (value*10) + c-'0';
// }
// else if(c==','|| c=='\0'){// then 2nd condtion eliminates the need of adding the last character
// if( value >=0 && value <=255) {// this is given in questions so check it no matter what
// arr[j++] = (uint8_t)value;
// (*count)++;
// }
// value =0;// this needs to be inside the else block
// }
// if(c=='\0') break;
// }
// combine 2 cchar to make a number, but how we store the indexes
//}
int main() {
char str[101];
fgets(str, sizeof(str), stdin);
// Remove newline
uint8_t i = 0;
while (str[i]) {
if (str[i] == '\n') {
str[i] = '\0';
break;
}
i++;
}
uint8_t arr[20];
uint8_t count = 0;
parse_csv_to_array(str, arr, &count);
for (uint8_t i = 0; i < count; i++) {
printf("%u", arr[i]);
if(i < count - 1){
printf(" ");
}
}
return 0;
}
// void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count){
// //extract every char and multipu by 10, add the next char until , is found, if , is found, store at the next arr position
// int i=0,value =0,j=0;
// for( i=0;str[i]!='\0';i++){
// int c = str[i];
// if(c >='0' && c<='9'){
// value=(value*10) + c-'0';
// }
// else if(c==','|| c=='\0'){
// if(value>=0 && value<=255){
// arr[j++]= (uint8_t)value;// typecast it as arr is uint8
// }
// value=0;
// }
/
// }
// *count = j;//need to return j+1 here
// }
void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count){
int i=0,j=0;
while(str[i]){
if(str[i]==','){
j++;
arr[j]=0;
i++;
continue;
}
arr[j] =(arr[j]*10) + (str[i]-'0');
i++;
}
(*count)=j+1;
}
Input
10,20,30
Expected Output
10 20 30