Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    int value = 0,j=0;
    for(int i=0; str[i]!='\n'; i++){
        int c = str[i];
        
        if( c>='0' && c<='9'){
            value = (value*10) + c-'0';
        }
        else if(c==','|| c=='\0'){// then 2nd condtion eliminates the need of adding the last character
            if( value >=0 && value <=255) {// this is given in questions so check it no matter what
                arr[j++] = (uint8_t)value;
                (*count)++;
        }
            
        value =0;// this needs to be inside the else block
    

    }

 if(c=='\0') break;

}

// combine 2 cchar to make a number, but how we store the indexes
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach