Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>

void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    *count = 0;
    uint16_t num = 0;
    int building_num = 0;
    
    while (1) 
    {
        if (*str >= '0' && *str <= '9') 
        {
            num = num * 10 + (*str - '0');
            building_num = 1;
        } 
        else if (*str == ',' || *str == '\0') 
        {
            if (building_num) {
                arr[*count] = (uint8_t)num;
                (*count)++;
                num = 0;
                building_num = 0;
            }
            if (*str == '\0') {
                break;
            }
        }
        str++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach