Parse Comma-Separated Integers into an Array

Code

#include <stdio.h>
#include <stdint.h>

#define COMMA (',')
#define NUM_ZERO ('0')
#define NUM_NINE ('9')
void parse_csv_to_array(const char *str, uint8_t *arr, uint8_t *count) {
    // Your logic here
    int num = 0;
    *count = 0;
    while(*str)
    {
        if((*str >= NUM_ZERO) && (*str <= NUM_NINE))
        {
            num = num*10 + (*str-NUM_ZERO);
        }
        else if(*str == COMMA)
        {
            *arr = num;
            arr++;
            (*count)++;
            num = 0;
        }
        str++;
    }
    *arr = num;
    (*count)++;    
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t arr[20];
    uint8_t count = 0;

    parse_csv_to_array(str, arr, &count);

    for (uint8_t i = 0; i < count; i++) {
        printf("%u", arr[i]);
        if(i < count - 1){
            printf(" ");
        }
    }
    return 0;
}

Solving Approach